 # ENGINEERING

Home Engineering
• Engineering
• Senior Project
• Projects
• 3 Doors Game Simulation
• Woodworking: Bedstand
• Woodworking: Desk
• Numbers Game
• Path Planning
• Snake Video Game AI
• Minimum Spanning Tree
• Heat Map
• MATLAB: Rocket Simulation
• MATLAB: Bike Suspension
• MATLAB: Thermal FEA SS
• MATLAB: Thermal FEA Tr
• Notes
• Statistics
• Steoscopic Estimates
• Cubed Roots
• Other
• Free Fall Distance
• Speed of Sound
• Travel
• Solar System Scale
• Videos
• Yellowstone Geysers
• Geysers and Waterfalls
• Yellowstone and Glacier
• Grinnell Glacier
• Yellowstone Geysers
• Photography

## Quick Freefall Distance Estimates

Measure distance off of a cliff by dropping a rock. Distance travelled by a free falling projectile follows the equation $$d=v_i+0.5at^2$$. Letting go of a rock from rest means that the distance to the bottom is $$0.5at^2$$ where $$t$$ is the time it takes for the rock to hit bottom and $$g$$ is the gravitational acceleration of $$32.174 ft/s^2$$. So distance in feet is approximately $$16t^2$$ where t is in seconds. Quick way to do this is to do $$t^2$$ times 10 and then take 1.5 times that number by adding half of it to it. Comparisons using this method to the actual calculation are shown in the table below. This approximation underestimates the distance by about 7%, but the mental measurement and rounding of $$t$$ is going to approximate too so the 7% rounding probably isn't the most signifcant source of error.

\begin{equation} d=v_i+0.5at^2 \end{equation} \begin{equation} d=0.5at^2 \end{equation} \begin{equation} d=0.5*32t^2 \end{equation} \begin{equation} d=16t^2 \end{equation} \begin{equation} d=1.5*10t^2 \end{equation}

Free Fall Time (s) Actual Distance (ft) Approximate Distance (ft)
1 16 15
2 64 60
3 145 135
4 258 240
5 403 375
6 580 540
7 789 735
8 1030 960
9 1304 1215
10 1610 1500